Mathematics, 21.04.2020 17:46 MaeWolfe

In a math class with 27 students, a test was given the same day that an assignment was due. There were 17 students who passed the test and 22 students who completed the assignment. There were 3 students who failed the test and also did not complete the assignment. What is the probability that a student passed the test given that they did not complete the homework

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Answer from: kiraswife

The probability that a student passed the test given that they did not complete the assignment is $\frac{15}{22}$ .

Step-by-step explanation:

The probability of an event E is the ratio of the number of favorable outcomes n (E) to the total number of outcomes N.

$P(E)=\frac{n(E)}{N}$

The union of two events is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

The intersection of the complements of two events is:

$P(A^{c}\cap B^{c})=1-P(A\cup B)$

The condition probability of an event given that another event has already occurred is:

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

Denote the events as follows:

A = students who passed the test

B = students who completed the assignment

Given:

N = 27

n (A) = 17

n (B) = 22

$n(A^{c}\cap B^{c})$ = 3

Compute the value of P (A ∪ B) as follows:

$P(A^{c}\cap B^{c})=1-P(A\cup B)$

$P(A\cup B)=1-P(A^{c}\cap B^{c})$

$=1-\frac{3}{27}\\$

$=\frac{24}{27}$

Compute the value of P (A ∩ B) as follows:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$P(A\cap B)=P(A)+P(B)-P(A\cup B)$

$=\frac{17}{27}+\frac{22}{27}-\frac{24}{27}\\$

$=\frac{17+22-24}{27}$

$=\frac{15}{27}$

Compute the value of P (A | B) as follows:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

$=\frac{15/27}{22/27}$

$=\frac{15}{22}$

Thus, the probability that a student passed the test given that they did not complete the assignment is $\frac{15}{22}$ .

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.

Answer from: Quest

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

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In a math class with 27 students, a test was given the same day that an assignment was due. There we...