Graph the circle which is centered at (3,-2) and has a radius of 5 units.

(x-3)^2+(y+2)^2=25

Step-by-step explanation:

c=(a,b) coordinates of center of circle

(x-a)^2+(y-b)^2=r^2 circle equation

a=3  b=-2  r=5

(x-3)+(y+2)=5^2

(x-3)^2+(y+2)^2=25

what is the question here

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option