In the card game bridge, each of 4 players is dealt a hand of 13 of the 52 cards.
what is the probability that each player receives exactly one ace?

The question is to show that the probability that each of the four players in a game of bridge receives one ace is=
= (24⋅48!⋅13^4)/52!
        My explanation so far is that there are 4! ways to arrange the 4 aces, 48! ways to arrange the other cards, and since each arrangement is equally likely we divide by 52!. I believe the 13^4 represents the number of arrangements to distribute 4 aces among 13 cards.