The probability that a person is accepted for admission to a specific university is 0.6. Determine the probability that exactly two of the next five people who apply to that university get accepted.

the probability that exactly two of the next five people who apply to that university get accepted is 0.23

Step-by-step explanation:

We would number of people that applies for admission at the university and gets accepted. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 0.6

q = 1 - p = 1 - 0.6

q = 0.4

n = 5

the probability that exactly two of the next five people who apply to that university get accepted is

P(x = 2) = 5C2 × 0.6^2 × 0.4^(5 - 2)

P(x = 2) = 10 × 0.36 × 0.064

P(x = 2) = 0.23

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer is b.)

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