What is the vertex of f(x) = x^{2} - 6x + 10?

(3, 1)

Step-by-step explanation:

First, find the equation of the axis of symmetry, which passes vertically through the vertex.  The coefficients of f(x) = x^{2} - 6x + 10 are a = 1, b = -6 and c = 10.  The formula for the axis of symmetry is

       -b                                                       -(-6)

x = and in this particular case, x = = 3            

       2a                                                       2(1)

Next, use this x-vaue (3) as the divisor in synthetic division.  The value of the remainder represents the y coordinate of the vertex.

3        1      -6     10

                  3     -9

           1      -3      1

Thus, the coordinates of the vertex are (3, 1).

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

3+x

step-by-step explanation: