F(x)=(7x−2)(5x−8)(x+5)(x−6)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 7, x, minus, 2, right parenthesis, left parenthesis, 5, x, minus, 8, right parenthesis, left parenthesis, x, plus, 5, right parenthesis, left parenthesis, x, minus, 6, right parenthesis has zeros at
x
=
−
5
x=−5x, equals, minus, 5,
x
=
2
7
x=
7
2

x, equals, start fraction, 2, divided by, 7, end fraction,
x
=
8
5
x=
5
8

x, equals, start fraction, 8, divided by, 5, end fraction, and
x
=
6
x=6x, equals, 6.

What is the sign of
f
ff on the interval
−
5
<
x
<
2
7

−5 7
2

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

what is the answer?