What is the solution system y=2/3x-2 y=-x+3

x = 3 , y = 0

Step-by-step explanation:

Solve the following system:

{y = (2 x)/3 - 2 | (equation 1)

y = 3 - x | (equation 2)

Express the system in standard form:

{-(2 x)/3 + y = -2 | (equation 1)

x + y = 3 | (equation 2)

Swap equation 1 with equation 2:

{x + y = 3 | (equation 1)

-(2 x)/3 + y = -2 | (equation 2)

Add 2/3 × (equation 1) to equation 2:

{x + y = 3 | (equation 1)

0 x+(5 y)/3 = 0 | (equation 2)

Multiply equation 2 by 3/5:

{x + y = 3 | (equation 1)

0 x+y = 0 | (equation 2)

Subtract equation 2 from equation 1:

{x+0 y = 3 | (equation 1)

0 x+y = 0 | (equation 2)

Collect results:

{x = 3 , y = 0

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24