Find the volume of the square pyramid, round to the nearest tenth :)

111.3 mm³

Step-by-step explanation:

First, find the height of the pyramid by using the Pythagorean Theorem

Imagine a right triangle going through the middle of the pyramid and perpendicular to the base. The slant of the pyramid is the hypotenuse.

The formula for the height of the pyramid is h²=l²-(s/2)², the slant height takes the place of c, the leg of the right triangle takes the place of b, and the height of the triangle takes the place of a

square root both sides: h=√20²-(22/2)²  

simplify exponents: h=√400-121

subtraction: h=√279

square root: h≈16.7

Then, solve for the volume like normal 1/3·b·h

20·16.7=334

334÷3≈111.3 mm³

it has the same slope and a different y-intercept

hope this : )

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft