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Mathematics, 19.04.2020 21:46 tori4023
\begin{cases}b(1)=-7 b(n)=b(n-1)+12 \end{cases}
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b(1)=−7
b(n)=b(n−1)+12
Find the 4^{\text{th}}4
th
4, start superscript, start text, t, h, end text, end superscript term in the sequence.
Answers: 3
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\begin{cases}b(1)=-7 b(n)=b(n-1)+12 \end{cases}
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