Jenny’s mother is 5 years older than twice Jenny's age. The sum of their ages is 62 years. This is represented by the equation x + 2x + 5 = 62, where x is Jenny’s age. Plug in the values from the set {12, 15, 18, 19} to find the value of x. The value that holds true for the equation is . So, Jenny is years old and her mother is years old.

Jenny´s age is 19 and her mother is 43.

Step-by-step explanation:

1. Plug in the first value of the set

41 is different from 62, so Jenny isn´t 12 years old.

2. Plug in the second value of the set

50 is different from 62, so Jenny isn´t 15 years old.

3. Plug in the third value of the set

59 is different from 62, so Jenny isn´t 18 years old.

4. Plug in the fourth value of the set

Therefore Jenny´s 19 years old.

5. Calculate Jenny´s mother age:

As the sum of their ages is 62 ages, we have the following equation

where

x=Jenny´s age

y=Jenny´s mother age

Therefore Jenny's mother age is 43 years old.

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step-by-step explanation:

im eatin up the 44

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!