For the simple harmonic motion equation d=5sin((pi/4)t), what is the period? .

The period of given harmonic function is 8

Step-by-step explanation:

Given: The simple harmonic motion

It is equation of simple harmonic motion.

We need to find the period of this function. It is sine function.

As we know the period of sine function is 2π

Period, sin x = 2π

If coefficient x is 1 then period is 2π

Period, sin (ax) = 2π/a

If coefficient of x is "a" then period is 2π divide by a

Period of given harmonic motion:

Hence, The period of given harmonic function is 8

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !