The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function J(d)=0.64⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on Jupiter. How long (in seconds) does it take a dropped object to fall 50 feet on Jupiter? Round your answer to the nearest hundredth.

1.13 seconds

Step-by-step explanation:

step 1

Find out how (in seconds) does it take a dropped object to fall 50 feet on Earth

we have

we have

substitute

step 2

Find out how (in seconds) does it take a dropped object to fall 50 feet on Jupiter

we have

For

Remember that

substitute

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)