Acar starts from rest and accelerates uniformly at 3.0 m/s2. a second car starts from rest 6.0 seconds later at the same point and accelerates uniformly at 5.0 m/s2. how long does it take the second car to overtake the first car?

20.62 seconds

Step-by-step explanation:

Intially, the first car starts from rest, therefore its displacement through the first 6 seconds can be found as follows:

Then, we need to find out its velocity at this point, which would be the first car's initial velocity for the second moment, when the second car accelerates:

To find out the moment that the second car overtakes the first one we should equal both cars' displacement equations and solve for t, keep in mind that a 54 m head start should be added to the first car's displacement:

Solving for t will yield a positive and a negative answer, since time can't be negative, only the positive answer should be considered, therefore, t = 20.62 s

n

step-by-step explanation:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.