Determine if the sequence (cosn/ n) converges or diverges. tell if it is absolutely or conditionally convergent

. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2. 

Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.by comparison test since cosn/n <= 1/n is convergent and 1/n is divergent by harmonic series so the series is conditionally converget

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