How does the volume of a cylinder change if the radius is quadrupled and the height is reduced to a third of its original size?

the answer is  1/3 pie r2h

Step-by-step explanation:

The volume of a cylinder is given by πr²h where, r is the radius of the cylinder and h is the height of the cylinder.

Also r=d/2 , where d is the diameter of the cylinder.

Therefore if the diameter is halved, the radius also gets halved ,i.e., it becomes r/2. Therefore the new volume = π(r/2)²h

=π(r²/4)h

=(1/4) πr²h

Therefore the volume becomes one-fourth of the initial volume.

answer: i believe c. is the answer sorry if i am wrong

step-by-step explanation:

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)