. A random sample of 80 jars of grape jelly has a mean weight of 568 g, with a standard deviation of 48.28 g. Construct a 99% confidence interval for , the true weight of a jar of jelly.

The 99% confidence interval is (553.7523, 582.2477)

Step-by-step explanation:

The formula for the confidence interval is

Where:

s = Standard deviation

z = t since the population variance is unknown

df = Degrees of freedom

n = Sample count

Which gives

= 568 2.64×5.4

(553.7523, 582.2477)

That is there is a 99% chance that the mean weight of a jar of jelly is

553.75 < μ < 582.25.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: