Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equation y = 2.5 x + 3 intersect the circle with radius 4 and center (0, 3)?

The point at which the line y  = 2.5·x + 3 intersect with the circle of radius 4 and center (0, 3) is x = 1.49

Step-by-step explanation:

Here we have the equation of a circle = (x - h)² + (y-k)² = r²

Where (h, k) is the coordinate of the center

Therefore, we have

(x - 0)² + (y - 3)² = 4²

Which gives x² + (y - 3)² = 16

Since the line y  = 2.5·x + 3 we have

x² + ( (2.5·x + 3 ) - 3)² = 16

x² + (2.5·x)² = 16

x² + 6.25·x² = 16

7.25·x² = 16

x² = 16/7.25 = 2.21

x = 1.49

That is the line y  = 2.5·x + 3 intersect with the circle of radius 4 and center (0, 3) at x = 1.49.

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