Find the value of sin(θ) for an angle θ in standard position with a terminal ray that passes through the point (-5, -12)

C. -12/13

Step-by-step explanation:

(-5,-12) is in the third quadrant

So sin would be negative

Hypotenuse = sqrt(5² + 12²)

sqrt(169)

13

sin(theta) = -12/13

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2