What is the slope of the line that passes through the points (3, -5)(3,−5) and (1, -5) ?(1,−5)?

Step-by-step explanation:

First given points

(3 , -5) and (3 , - 5)

Now

Slope (m)

=y2 -y1

x2 -x1

= -5 + 5

3 - 3

= 0/0

= undefined

Now

Next point

(1 , -5) and (1 , -5)

slope(m)

=y2 - y1

x2 - x1

= - 5 + 5

1 - 1

= 0/0

= undefined

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

3; 9 is 8 to -4

step-by-step explanation: