What is the equation of the line that passes through the point (8,1) and has a slope
of?

Step-by-step explanation:

hello :

Use the point-slope formula.

y - y_1 = m(x - x_1)      when : x_1 = 8  and  y_1 = 1

the equation is : y - 1 = m(x - 8)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.