Which choice shows the coordinates of B’ if the trapezoid is reflected across the x-axis?

On a coordinate plane, trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1).

(–7, 2)

(2, –7)

(7, –2)

(–2, 7)

Given:

Given that the coordinates of the trapezoid ABCD.

The coordinates are A(2,2), B(7,2), C(5,1) and D(3,1)

Also, given that the trapezoid is reflected across the x - axis.

We need to determine the coordinates of the point B' after the reflection across the x - axis.

Coordinates of the point B':

The general rule to reflect the point across the x - axis is given by

Substituting the coordinate (7,2) in the above general rule, we get;

Thus, the coordinate of the point B' after the reflection across the x - axis is (7,-2)

Hence, Option c is the correct answer.

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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