A spinner with four equal sections of blue, green, yellow, and red is spun 100 times. It lands on blue 14 times, green 10 ten times, yellow 8 times, and red 68 times.

The relative frequency of landing on red = 0.68 = 68%

Step-by-step explanation:

- The spinner has 4 equal sections; blue, green, yellow, and red.

- It is spun 100 times.

- It lands on blue 14 times, green 10 ten times, yellow 8 times, and red 68 times.

The relative frequency of landing on red? Express your answer as a percent.

The relative frequency of landing on any section = (number of times the spinner lands on that section) ÷ (total number of times the spinner is spun)

The relative frequency of landing on red = (68) ÷ (100) = 0.68.

In percentage, 0.68 = 68%

Hope this Helps!!!

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!