In ΔCDE, the measure of ∠E=90°, the measure of ∠C=16°, and EC = 65 feet. Find the length of DE to the nearest tenth of a foot.

Given:

Given that the triangle CDE is a right triangle.

The measure of ∠E is 90° and the measure of ∠C is 16° and the length of EC is 65 feet.

We need to determine the length of DE.

Length of DE:

The length of DE can be determined using the trigonometric ratio.

Thus, we have;

where the angle is 16° and the side opposite to the angle is DE and the side adjacent to the angle is EC.

Substituting the sides, we get;

Substituting DE = 65, we have;

Multiplying both sides by 65, we have;

Thus, the length of DE is 18.6 feet.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

answer: 60%

explanation:

÷

= 60%