Abowl contains 8 blue marbles and 5 green marbles. elizabeth randomly draws 4 marbles from the bowl. she does not replace the marbles after each draw. what is the probability that she draws 1 blue marble and 3 green marbles?
a.
b.
c.
d.

Probability ( 1 blue marble and 3 green marbles) = ( Blue, green, green, green) + ( green, blue, green, green) + ( green, green, blue, green) + ( green, green, green, blue) = { (8/13) × (5/12) × (4/11) × (3/10) } + { (5/13) × (8/12) × (4/11) × (3/10) } + { (5/13) × (4/12) × (8/11) × (3/10) } + { (5/13) × (4/12) × (3/11) × (8/10) } = (4/143) + (4/143) + (4/143)+ (4/143) = 16/143 If the answer does not correspond to yours, do tell me. I'll try to correct mine