A DG=12
B EF=12
C DF=24

Thank you

When a one diagonal of a quadrilateral is the perpendicular bisector of the other diagonal we get a kite.

We don't necessarily get a rhombus; we can imagine G way up higher with the same perpendicular angle and congruent segments.

Let's call the center C.   We have angle FCE is congruent to angle DCE, as they're both right angles.  Side CE is congruent to itself and FC=DC so by SAS (also called LL in this right triangle case) we have congruent triangles FCE and DCE, so by corresponding parts, EF=ED

EF=12

answer: i can’t tell you that

step-by-step explanation: