Megan is flying a kite that is 60 yards above the ground. The length of the kite string is 100 yards. What is the distance from Megan to the point on the ground directly below the kite.

Given:

The height of the kite from the ground = 60 yards

The length of the string of the kite = 100 yards.

To find the distance from Megan to the point on the ground directly below the kite.

Formula

By Pythagoras theorem for a right angle triangle we get,

where, h be the hypotenuse, b be the base, l be the another side along right angle.

Now,

Here, putting l = 60 and h = 100 we get,

    =

Here we will take b = 80 because the length cannot be measured in negative.

Hence, the distance from Megan to the point on the ground directly below the kite is 80 yard. ​

Thus, Option D is the correct answer.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0