Помогите пожалуйста
( / - дробная черта)
1. Решите уравнение 1 способом (Перенос
...
Mathematics, 17.04.2020 15:15 nofer
Помогите пожалуйста
( / - дробная черта)
1. Решите уравнение 1 способом (Перенос
всех слагаемых из правой части уравнения
в левую)
а) 11 + 2x = 55 + 3x
б) -15 - 3x = -7x + 45
в) -3x - 17 = 8x - 105
г) 0,6x − 5,4 -= -−0,8 x + 5,8
д) 5/6x + 16= 4/9 x + 9
2. Решите уравнение 2 способом (Переносом
слагаемых, содержащих переменную, из
правой части в левую, а не содержащих
переменную, из левой части в правую.
а) 2(2 + y) = 19 - 3y
б) (4 - c) + 2(c - 3) = -13
в) -3(3b + 1) - 12 = 12
г) 0,3(8 − 3y) = 3,2 −0,8(y − 7)
д) 5/6 (1/3 x - 1/5) = 3x = 3 1/3
пожалуйста решите именно тем способом который указан. надеюсь на вас
Answers: 1
Mathematics, 20.06.2019 18:04
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
Answers: 2
Mathematics, 21.06.2019 20:00
Does anyone know how to solve and graph this: 4 + | a + 2 | < 7the only part i don't get is the "4 +"
Answers: 2
Mathematics, 21.06.2019 20:30
Answer asap ill give ! ’ a sample of radioactive material decays over time. the number of grams, y , of the material remaining x days after the sample is discovered is given by the equation y = 10(0.5)^x. what does the number 10 represents in the equation? a. the half-life of the radioactive material, in days b. the amount of the sample, in grams, that decays each day c. the time, in days, it will take for the samples to decay completely d. the size of the sample, in grams, at the time the material was discovered
Answers: 1
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