Consider a school with two classes, A and B. In class A there are 15 girls and 17 boys. In class B, there are 19 girls and 10 boys. Both classes plan extracurricular activities for which each class forms a committee consisting of three students. How many possible committees are there such that the total of committee members of both classes combined consists of 4 girls

7700 committee

Step-by-step explanation:

Given that  In class A there are 15 girls and 17 boys.  And In class B, there are 19 girls and 10 boys

To find  possible committees of 3 such that the total of committee members of both classes combined consists of 4 girls, we will use combination technique

(15C2 × 17C1) + (19C2 × 10C1)

Or

(15C1× 17C2) + (19C3 ×10C0)

Or

(15C3 × 17C0) + (19C1 × 10C2)

Note that "or" means addition

(1785 + 1710) + (2040 + 855) + (455 + 855)

= 3495 + 2895 + 1310

= 7700 committee

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step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.