An opaque bag contains 3 green marbles and 3 red marbles. An opaque bag contains 3 green marbles and 3 red marbles. Two marbles are randomly drawn one at a time without replacement. Find the probability the 2nd marble drawn is a red marble, given the first marble drawn was red.

40% chance

Step-by-step explanation:

After removing the first red marble from the bag, there will be 3 green marbles and 2 red marbles left. This gives you a 2/5 chance to draw another red one, or a 40% chance.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

answer: its the third option.

step-by-step explanation:

i just took the test.