Why does this show that lambda Superscript negative 1λ−1 is defined? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. By definition, x is nonzero and A is invertible. So, the previous equation cannot be satisfied if lambdaλequals=nothing. B. Since the product lambda Superscript negative 1λ−1x must be defined and nonzero, lambda Superscript negative 1λ−1 must exist and be nonzero. C. Since x is an eigenvector of A, Upper A Superscript negative 1A−1 and x are commutable. By definition, x is nonzero, so the previous equation cannot be satisfied if lambdaλequals=

good job you smart son of a gun you are smarter that einstein. 7

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

$6.42

step-by-step explanation:

answer: the answer is fre sha voca do

step-by-step explanation: