Show that there does not exist any real number c such that the following function f(x) would be a valid probability density function: f(x) = ( c=(1 + x); if x > 0 0; otherwise: Repeat if f(x) were given by: f(x) = ( c=(x); if x > 0 0; otherwise: Hint: To be a valid density function f must be non-negative and integrate to 1.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

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step-by-step explanation:

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step-by-step explanation: