What are the domain range of f(x)= 1/5 power of x

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

I'm assuming you mean the function .  That's usually written

f(x) = x^(1/5) with the ^ meaning "to the power of..." and the fraction exponent in parentheses so as not to be confused with x^1/5 which could mean x to the first power, divided by 5.

Fractional exponents are used to indicate roots.  In this case, x is being raised to the 1/5 power, so this is the fifth root of x, written .  The 5 is called the root index.

For odd roots, like this one, the domain is all real numbers--x can be any number at all.  So the domain is all real numbers.

The range is also all real numbers.  Attached is a graph of this function. It might not look like it, but the graph rises to the right to any height.  The larger x gets, the larger the 5th root gets.  A similar thing happens on the left--the smaller x gets, the smaller the 5th root gets.

EDIT: see the comment.  For the function , the domain is all real numbers. The range is positive real numbers.  I'll attach a graph!

the least common denominator is 40

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form