The box plots show the average speeds, in miles per hour, for the race cars in two different races.

Average Speeds of Cars in Race A
2 box plots. The number line goes from 120 to 170. For Race A, the whiskers range from 120 to 170, and the box ranges from 143 to 165. A line divides the box at 153. For Race B, the whiskers range from 125 to 165, and the box ranges from 140 to 150. A line divides the box at 145.
Average Speeds of Cars in Race B

Which statement compares the median speeds for the data in the two box plots?
The median speed in race A is about 142 miles per hour, and the median speed in race B is about 140 miles per hour.
The median speed in race A is about 120 miles per hour, and the median speed in race B is about 125 miles per hour.
The median speed in both races is about 165 miles per hour.
The median speed in race A is about 153 miles per hour, and the median speed in race B is about 145 miles per hour.

both equations and proportions are better.

6e14 is the answer.

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.