Haley randomly chooses a gumball out of a container containing 9 cherry gumballs and 3 chocolate gumballs. She places the gumballs in her pocket and chooses a second gumball. Find the probability that the first gumball is cherry and the second one is chocolate.

8.3%

Step-by-step explanation: we use the formula 1/12x100 to give us 8.3 % and then for chocolate we do the same to get the same percentage 8.3%. so the probability that haley chooses a cherry gumball and then a chocolate gumball is 8.3%.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

m=-16

step-by-step explanation: