Where is the hole in the equation (x-2)/(x^2-4)

x = 2, or at the point (2, 1/4)

Step-by-step explanation:

Factor the denominator (difference of two squares).

There is a common factor of which indicates there is a hole at (where ).

If you're used to answering a question like this with the complete coordinates of a point, put into a simplified fraction, by cancelling the common factor.

Substitute 2 for x.

The hole is at the point (2, 1/4).

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

the answer for your question is

step-by-step explanation: