A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is:

The height of the frustum?

5

Step-by-step explanation:

According to the question, A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12.We are now asked to find the height of the frustum.

---The height of this frustum is equal to the distance of its smaller base from the center of the sphere.

Therefore,it is assigned the pattern

H = √(r1² - r2²

Where r1 is the radius of the sphere

And r2 is the radius of the other base of the frustum

H is the height that we are looking for

H = √(13² - 12²)

= √( 169 - 144 )

= √ 25

H = 5

55

step-by-step explanation:

i dont know what you want me to answer for this but im guessing 2: 11?