A division of a company has over 200 employees, 40% of which are male. Each month, the company randomly

selects 8 of these employees to have lunch with the CEO.

What are the mean and standard deviation of the number of males selected each month?

You may round your answers to the nearest tenth.

mean:?

males

standard deviation:?

males

Step-by-step explanation:

-The number of males in the company is:

#Given the proportion of males in the population is 40%(p=0.4) and the sample size, n=8

-The mean and standard deviation of a sample proportion is calculated as follows:

Hence, the mean of males is 3.2 and the standard deviation is 0.2

1/6

step-by-step explanation:

i believe it’s 165 because if u add 137 and 58 u get 195 and then subtract that from 360 and there’s ur answer