Can someone do 11??? Please help I don’t want to fail my class

Recall that the tangent of an angle is equal to the ratio of the opposite over adjacent sides

tan(angle) = opposite/adjacent

For reference angle Y, the opposite side is XZ = 6 and the adjacent side is XY = 7, so,

tan(Y) = XZ/XY = 6/7

For tan(Z), things will swap. The opposite side is now XY = 7 and the adjacent side is now XZ = 6

tan(Z) = XY/XZ = 7/6

We do not use the hypotenuse sqrt(85) at all in this problem because the tangent ratio does not involve the hypotenuse.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

c

step-by-step explanation: