Find either of the values of x
2x^2+3x-2=3

x = 1 or x = -5/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + 3 x - 2 = 3

Divide both sides by 2:

x^2 + (3 x)/2 - 1 = 3/2

Add 1 to both sides:

x^2 + (3 x)/2 = 5/2

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = 49/16

Write the left hand side as a square:

(x + 3/4)^2 = 49/16

Take the square root of both sides:

x + 3/4 = 7/4 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

x = 1 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

x = 1 or x = -5/2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

y= -2x+4, have a great day