Commuting. there are two routes he could take to work. Aneighbor who has lived there a long time tells him Route Awill average 5 minutes faster than Route B. The man decides to experiment. Each day he flips a coin to determine which way to go, driving each route 20 days. He finds that Route Atakes an average of 40 minutes, with stan- dard deviation 3 minutes, and Route B takes an average of 43 minutes, with standard deviation 2 minutes. His- tograms of travel times for the routes are roughly sym- metric and show no outliers. a. Find a 95% confidence interval for the difference in average commuting time for the two routes. b. Should the man believe the old-timer s claim that he can save an average of 5 minutes a day by always driving Route A

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

Step-by-step explanation:

Given:  

n_1 = 20

x_1= 40

s_1 = 3

n_2 = 20

x_2= 43

s_2 = 2

d_f = 33.1

c = 95%. 0.95

(a) Determine the t-value by looking in the row starting with degrees of freedom df = 33.1 > 32 and in the column with c = 95% in the Student's t distribution table in the appendix:  

t/2 = 2.037  

The margin of error is then:  

E = t/2 *√s_1^2/n_1+s_2^2/n_2

E = 2.037  *√3^2/20+s_2^2/20

  = 1.64

The endpoints of the confidence interval for u_1 — u_2 are:  

(x_1 — x_2) — E = (40 — 43) — 1.6423 = —3 — 1.6423= —4.6423

(x_1 - x_2)  + E   = (40 — 43) + 1.6423 = —3 + 1.6423= —1.3577  

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

i think the correct option is the second option.