Help please! 10+ points!! Include a diagram and solution :)

A lighthouse is observed by a ship�s office on watch at an angle of 42 degree to the path of the ship.

At the next sighting the lighthouse is observed at an angle of 90 degree to the path of the ship.

The distance travel between sightings is 1800 m .

To the nearest meter, how far away is the ship to the lighthouse at this second sighting?

:

This situation, forms a right triangle, we can use the tangent of 42 degrees

where

side adjacent = 1800 m

side opposite = distance (d) from the ship to the lighthouse when the angle is 90

:

tan(42) = d%2F1800

d = .9004 * 1800

d ~ 1621 meters from the ship to the light

Step-by-step explanation:

A lighthouse is observed by a ship�s office on watch at an angle of 42 degree to the path of the ship. At the next sighting the lighthouse is observed at an angle of 90 degree to the path of the ship. The distance travel between sightings is 1800 m .To the nearest meter, how far away is the ship to the lighthouse at this second sighting?

mr. graef told us it is 13 pints

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine