You are on a fishing boat that leaves its pier and heads east. After traveling for 24 miles, there is a report warning of rough seas directly south. The captain turns the boat and follows a bearing of S40°W for 13.5 miles. The pier is labeled point A, the turning point is labeled point B, and the ships current position is labeled C. Line segment A B lies on the east/west line where A is to the left of B and is labeled 24 miles. Line segment B C is 40 degrees west of south and is labeled 13.5 miles. Line segment C A is labeled b. There is a compass rose where north is up. 40 degrees 13.5 24 a. At this time, how far are you from the boat's pier? b. What bearing could the boat have originally taken to arrive at this spot?

(a)18.49 Miles

(b) or

Step-by-step explanation:

(a)From the diagram, Angle B=50 degrees.

The distance of the boat at C from the boat's pier at A is the line AC.

We solve for AC using the Cosine rule.

The distance of the boat from the pier is 18.49 miles.

(b)The bearing the boat could have originally taken to arrive at this spot is the bearing of C from A.

to calculate this, we find first the Angle at A.

Using Sine rule

Therefore the bearing of C from A

In Compass Bearing

Bearing of C from A

The boat could have originally taken a bearing of degrees to arrive at C.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled