A recent survey conducted by Wall Street Journal indicates that the average reading time of 100 its readers/participants was 45 minutes and the standard deviation was 20 minutes. The journal is now planning another survey study. If the acceptable error is 3 minutes and a confidence level of 99% is desired, what would be the minimum sample size needed for the upcoming survey?

The minimum sample size needed for the upcoming survey

n = 289

Step-by-step explanation:

Explanation:-

step:- (i)

Given A recent survey conducted by Wall Street Journal indicates that the average reading time of 100 its readers/participants was 45 minutes and the standard deviation was 20 minutes

sample size n= 100

mean =45 min and standard deviation = 20 minutes

If the acceptable error is 3 minutes and a confidence level of 99% is desired

Given margin of error is '3' min

Step(ii):-

Margin error

We know that margin of error  =

Now we determine the sample size

The 99% of level of significance 'Z' value = 2.57

n = (17)^2

n = 289

Conclusion:-

The minimum sample size needed for the upcoming survey

n = 289

Verification:-

Margin error =

Given data of margin error also =3

so both are equal

There fore the minimum sample size needed for the upcoming survey

n = 289

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

answer: at first, in 1635, the evening meetings had been just for women . .

what relationship between ideas is shown in the text above?

question 1 options:

location of events

similarity of events

timing of events

examples of an idea

step-by-step explanation: