In a certain population of mussels (Mytilus edulis), 80% of the individuals are infected with an intestinal parasite. A marine biologist plans to examine 100 randomly chosen mussels from the population.

a) Find the probability that 85% or more of the sampled mussels will be infected using normal approximation to binomial distribution.

The probability that 85% or more of the sampled mussels will be infected is 0.1057.

Step-by-step explanation:

Let X = number of mussels infected with an intestinal parasite.

The probability that a random selected mussel is infected with an intestinal parasite is, p = 0.80.

A random sample of n = 100 mussels from the population are examined by a marine biologist.

The random variable X follows a Binomial distribution with parameters n = 100 and p = 0.80.

But the sample selected is too large, i.e. n = 100 > 30.

So a Normal approximation to binomial can be applied to approximate the distribution of , the sample proportion of mussels infected with an intestinal parasite, if the following conditions are satisfied:

Check the conditions as follows:

n × p = 100 × 0.80 = 80 > 10

n × (1 - p) = 100 × (1 - 0.80) = 20 > 10

Thus, a Normal approximation to binomial can be applied.

So,  the distribution of is:

Compute the probability that 85% or more of the sampled mussels will be infected as follows:

Apply continuity correction:

*Use a z-table for the probability.

Thus, the probability that 85% or more of the sampled mussels will be infected is 0.1057.

your answer is a

step-by-step explanation:

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answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6