Captain Kevin has a ship, the H. M.S. Khan. The ship is two furlongs from the dread pirate Ben and his merciless band of thieves. The Captain has probability 3 5 5 3 start fraction, 3, divided by, 5, end fraction of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1 5 5 1 start fraction, 1, divided by, 5, end fraction.

The probability that the pirate hits the Captain's ship, but the Captain misses

= 2/25) = 0.08

Step-by-step explanation:

Probability of the Captain hitting the pirate's ship = P(C) = (3/5)

Probability of the Captain NOT hitting the pirate's ship = P(C') = 1 - (3/5) = (2/5)

Probability of the pirate hitting the Captain's ship = P(p) = (1/5)

Probability of the pirate NOT hitting the Captain's ship = P(p') = 1 - (1/5) = (4/5)

If they both fire their cannons at the same time, the probability that the pirate hits the Captain's ship, but the Captain misses.

The required probability is P(C' n p)

Since the two events are independent of each other, P(C' n p) = P(C') × P(p)

The probability that the pirate hits the Captain's ship, but the Captain misses

= (Probability that the Captain does NOT hit the pirate's ship) × (Probability that the pirate hits the Captain's ship)

= (2/5) × (1/5) = (2/25) = 0.08

Hope this Helps!!!