How much does each fish weigh if all the fish total weigh 240. The 1 fish weighs twice as much as the 2 fish and the 3 fish weighs twice as much as the 1 fish. The weight of the last fish weighs 5 times as much as the 2 fish

S = 20

F = 40

T = 80

L = 100

Step-by-step explanation:

Let 1st fish= F

2nd fish = S

3rd fish = T

4th fish = last fish = L

From the question,

The 1st fish weighs twice as much as the 2nd fish. I.e

F = 2S (1)

and the 3rd fish weighs twice as much as the 1st fish. I.e

T = 2F (2)

But F = 2S from (1) substitute for F

T = 2(2S)

T = 4S (3)

The weight of the last fish weighs 5 times as much as the 2nd fish. I.e

L = 5S (4)

We have,

1st + 2nd + 3rd + 4th = 240 I.e

F + S + T + L = 240 (5)

Substitute F, T and L into (5)

2S + S + 4S + 5S = 240

12S = 240

S = 20

From equation (1)

F = 2S = 40

From equation ( 3)

T = 4S = 80

From equation (4)

L = 5S = 100

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

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step-by-step explanation: