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Mathematics, 15.04.2020 21:05 SorayaC9669

Bβˆ’(βˆ’18)+cb-\left(-\dfrac{1}{8}\righ t)+c bβˆ’(βˆ’ 8 1 )+c b, minus, left parenthesis, minus, start fraction, 1, divided by, 8, end fraction, right parenthesis, plus, c where b=2b = 2 b=2 b, equals, 2 and c=βˆ’74c = -\dfrac{7}{4} c=βˆ’ 4 7

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