What would be the normal weight of a chair if the coefficient of friction between it and the floor is 0.38 and the force needed to push it is 88 lbs.?

Step-by-step explanation:

μ = 0.38

F = 88lbs

N = ?

The force acting on a surface F =

F = μN

Where F = force acting on the body

N = Normal force

μ = coefficient of static friction

N = F / μ

N = 88 / 0.38

N = 231.578N

N = 231.6N

The normal force acting on the body is 231.6N

answer:

c 60% on edg

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5