Given that x and y are positive integers and (x·2)+x(2^2)+(y·2^3)+(y·2^4)=42, what is the value of xy?

pls helpp

The numbers are x = 3 and y = 1. Therefore the value of xy is 3.

Step-by-step explanation:

In order to calculate the numbers we will simplify the equation, this is done bellow:

2*x + x(2^2) + (y*2^3) + (y*2^4) = 42

2*x + 4*x + 8*y + 16*y = 42

6*x + 24*y = 42

We can divide the whole equation by 6, so we have:

x + 4*y = 7

The only possible combination of numbers that are positive and integers that will make the equation valid is x = 3 and y = 1. Therefore he value of xy is 3.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x