What proportion of people get most of their news on theInternet? According to a recent poll,36% get most of their news from the Internet. Complete parts (a) through(e).

a.

To conduct a follow-up study that would provide 95% confidence that the point estimate is correct to within
plus or minus ±0.05 of the populationproportion, how large a sample size is required?

A sample size of nothing people is required.

(Round up to the nearest integer.)

b.

To conduct a follow-up study that would provide 99% confidence that the point estimate is correct to within

plus or minus ±0.05 of the populationproportion, how many people need to be sampled?

A sample size of nothing people is needed. (Round up to the nearest integer.)

c.

To conduct a follow-up study that would provide 95% confidence that the point estimate is correct to within

plus or minus ±0.02 of the populationproportion, how large a sample size is required?

.d.

To conduct a follow-up study that would provide 99% confidence that the point estimate is correct to within

plus or minus ±0.02 of the populationproportion, how many people need to be sampled?

.e.

Discuss the effects of changing the desired confidence level and the acceptable sampling error on sample size requirements. Select all that apply.

A. The higher the level of confidence desired, the larger is the sample size required.

B. The smaller the sampling errordesired, the larger is the sample size required.

C. The higher the sampling errordesired, the larger is the sample size required.

D. The smaller the sampling errordesired, the smaller is the sample size required.

E. The smaller the level of confidence desired, the larger is the sample size required.

F.

The higher the level of confidence desired, the smaller is the sample size required.

G.

There are no effects on the sample size requirements.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

x< 2

step-by-step explanation: